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Robert McKeown: Hello, and welcome to ALEKS

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walkthrough video number two. I'm Professor

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Robert McKeown, and I'm very happy that you

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decided to check out my video. Today we're going

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to take a closer look at equations. And we're

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also going to learn about mathematical notation.

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We can think of mathematical notation as a

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language, just like English, or Mandarin, or

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French is a language. It's the language of

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mathematics. And so I hope by the end of today's

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video, or perhaps after a little bit of

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practice, you'll become comfortable translating

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English into math notation, and translating math

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notation back into English. Now, I'm not going

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to try and cover every single topic. In ALEKS,

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I'm just going to cover the topics that I feel

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are most helpful to you. Either because they're

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important or because they're fundamental. And by

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learning them, it's easy to go further into more

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detail. As usual, with these videos, what I

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expect from you, I expect you to have your

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pencil paper, you can print out the slides. If

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you have lots of devices, maybe you want to even

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write your notes on a second device on a tablet

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or something like that. Whatever works for you,

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but I highly recommend you work along with the

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problems or try the problem first, and then

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watch the video. So if you're ready, I'm ready.

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Mathematics has its own language of symbols.

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These symbols, give you instructions and

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describe some of the mathematical values and

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variables that you'll be working with. Like any

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language, we can translate it into English. If

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you look at the slide in front of you, you can

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see some mathematical symbols in the left

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column, how we would the English expression so

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how we would actually say these things, and then

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I've given you a little bit of their meaning.

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And so I want to take a few moments to explain

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to you interval and set notation that'll help

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you answer some of the questions and ALEKS take

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a moment and familiarize yourself with the

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table. Looking at the example, I can write this

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mathematical symbol in English, which I'm going

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to do for you now this is an interval

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and four is the low point or the lowest value

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and the interval runs up to its largest value.

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And since it really has no upper limit, there is

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no largest value. We represent that concept with

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the infinity symbol, right. So infinity symbols

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are not numbers, infinity symbol represents a

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concept. No upper limit on this.

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The next thing I want you to notice is that we

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have a square bracket. square bracket represents

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a close bracket. And so what does this mean?

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This means the interval includes the value for

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so in English,

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x is in. Right That's our n symbol the interval

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for To infinity,

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where infinity is representing a concept that

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there's no, there's no upper limit, whatever

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number however big a number, you can imagine, X

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can take on that value, there's one more thing

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I'd like to show you. And that's an alternative

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way of expressing this thing. Mathematically,

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and so I could write x is greater than and equal

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to, or I should say or equal to x is greater

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than or equal to four. And if I write that, you

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know, these things are equivalent. So that's an

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alternative way of writing it. And that's going

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to come in handy when you look at the problems

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on ALEKS. And when they ask you to go from an

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expression like x is greater than or equal to

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four to writing the the set or interval

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notation. Now let's go to the next slide. And

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let's take a look at the next example. So the

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table is the same. But the example down here is

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a little bit different. So let's go through this

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example. Now, the variable v is in the interval

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from negative five to negative two. Now, I said

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that, but what about the round brackets and the

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square brackets. So now what values can be take

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on? Well, we've got around bracket. And so v

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must be larger than negative five. And we've got

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a square bracket over here. And so v has to be

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less than or equal to negative two. Now, here I

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am on ALEKS. And so we have a question from

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Alex. It says solve the compound inequality. And

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so we're given two equations. This time, both

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equations have X as the unknown variable. And

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then we're told write this solution in interval

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notation. If there is no solution to these two

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inequalities, enter that funny looking zero, or

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that circle with a line through it, which is our

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null set, also sometimes called the empty set.

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Now you are going to work on this problem on a

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piece of paper, I'm going to take us back to our

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slides. And so here we are in the slides. And we

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want to write the solution to this in interval

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notation. So we'll start with this equation on

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the left hand side, I've got three X, I'll

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subtract six of both sides of the equation. So

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I'll just write that as

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we have x must be less than six. Now let's take

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a look at our other expression. So I see I've

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got a two x minus two on the left hand side, I'm

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going to add two to both sides of the equation.

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So I'm going to have two x is less than or equal

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to negative eight plus two. So that gives me two

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x is less than or equal to negative six, and x

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is less than or equal to divide in both sides of

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the equation by two, I get negative three. Now,

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the question had a very important instruction,

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very important instruction that I have ignored

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so far, and that is right here. So the question

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is saying that either the question on the left

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is correct or true. And the question on the

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right is, or the question on the right is

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correct. And true. So x must be less than six,

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or it must be less than and equal to negative

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three. So I'll draw a real number line. And I'm

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going to have six over here, and negative three

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over there. Now, if I want to start with this

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equation, now I'm going to write the equation

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over here. And I'll write this one over here as

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well.

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And so you can see that if x is less than six,

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the inequality is satisfied. But I'm going to

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draw a circle, an empty circle, here to

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represent that this is open.

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And that's an analogy. You can think of that as

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the an open bracket that we saw previously.

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Then over here, x can be equal to negative

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three. So I'm going to draw a solid.to represent

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it as being closed. So a circle or a dot with

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hollow in the middle, that's open, solid dots

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going to be closed. Now we can go over to ALEKS

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and solve the question or I should say put the

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answer, ALEKS. Before we move over to ALEKS,

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though, maybe I should point out to you that,

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notice that if x is less than or equal to three,

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then x is also less than six. And since either

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one of these inequalities has to hold, the

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correct answer is going to be x must be less

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than six. And so x is in the set negative

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infinity to six with a round bracket to

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represent that x cannot take on the value of

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six, it's an open set can't take on the value

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six. So here we are in ALEKS, we have the same

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question that we're given before. What is the

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interval here that we're looking for? Well, we

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know that it's going to be rounded brackets. and

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the value of x can be as low a number as you can

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imagine, so I'm going to put a negative infinity

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symbol in there. And the maximum value it can

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take on is something just a little bit less than

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six. And so we represent or I should say, a

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little bit less than Oh, no, sorry, that was

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six. any value less than six. Now I'll check my

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answer. And we got the correct answer on ALEKS.

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The interval of x is going to be between

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negative infinity and six but it cannot take on

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the value six. So we have the rounded bracket.

